Hydraulics

Hydraulics Bachelor of Engineering(BE) videos According to syllabus of Institute of Engineering(IOE), Tribhuvan University (TU)

Advanced 5 (6 Reviews ) 126 Students enrolled
Last updated Thu, 19-May-2022 Nepali
What will I learn?
  • After Completion of this Course, Students will get complete knowledge of hydraulics, based on syllabus of IoE and will be able to secure good score in IoE exam.

Curriculum for this course
258 Lessons 48h 0m
1. Marks Distribution
1 Lessons 5m
  • Syllabus and Marks distribution 5 Minutes Free
  • 1. Pipe flow (differences between pipe flow and open channel flow) 13 Minutes Free
  • 2. Reynold's experiment and flow based on Reynold's number 8 Minutes Free
  • 3. Laminar flow in circular pipe (expression for shear stress) 14 Minutes
  • 4. Laminar flow in circular pipe (velocity distribution) 8 Minutes
  • 5. Relation between average velocity and maximum velocity 9 Minutes
  • 6. Laminar flow in circular pipe (head loss) 7 Minutes
  • 7. Numerical 1 (laminar flow) 24 Minutes
  • 8. Numerical 2 (laminar flow) 19 Minutes
  • 9. K.E. and momentum correction factors 7 Minutes
  • 10. Calculation of K.E. and momentum correction factors for laminar flow 10 Minutes
  • 11. Turbulent flow (basic features) 9 Minutes
  • 12. Shear stress development in turbulent flow 5 Minutes
  • 13. Boussinesq theory of turbulence 4 Minutes
  • 14. Reynold's principle of turbulence 5 Minutes
  • 15. Prandtl's mixing length theory 8 Minutes
  • 16. Velocity distribution for turbulent flow (Prandtl's universal velocity distribution, applicable for both smooth and rough pipe) 12 Minutes
  • 17. Analysis of velocity distribution in turbulent flow 8 Minutes
  • 18. Hydrodynamically smooth and rough pipe 7 Minutes
  • 19. Velocity distribution equation for turbulent flow in smooth pipe 13 Minutes
  • 20. Velocity distribution equation for turbulent flow inrough pipe 4 Minutes
  • 21. Velocity distribution equation in terms of mean velocity 9 Minutes
  • 22. Relation between velocity at any point and average velocity, location of average velocity 8 Minutes
  • 23. Darcy-Weisbach equation 17 Minutes
  • 24. Resistance to flow of fluid in smooth and rough pipes 24 Minutes
  • 25. Numerical 1 (Turbulent flow) 16 Minutes
  • 26. Numerical 2 (Turbulent flow) 10 Minutes
  • 27. Numerical 3 (Turbulent flow) 10 Minutes
  • 28. Numerical 4 (Turbulent flow, concept of hydraulic radius) 15 Minutes
  • 29. Numerical 5 (Turbulent flow) 13 Minutes
  • 30. Energy losses in pipe 5 Minutes
  • 31. Loss of head due to sudden enlargement of pipe 8 Minutes
  • 32. Head loss due to sudden contraction of pipe 7 Minutes
  • 33. Other types of minor losses 5 Minutes
  • 34. HGL and TEL 9 Minutes
  • 35. Numerical (minor losses) 11 Minutes
  • 36. Numerical (HGL and TEL) 25 Minutes
  • 1. Three categories of pipe flow problems 7 Minutes
  • 2. Category 1 (procedure to solve) 3 Minutes
  • 3. Numerical (Category 1) 6 Minutes
  • 4. Category 2 (procedure for solving) 5 Minutes
  • 5. Numerical 2 (Category 2) 11 Minutes
  • 6. Numerical 4 (Category 2) 8 Minutes
  • 7. Category 3 (procedure for solving) 4 Minutes
  • 8. Numerical 4 (Category 3) 10 Minutes
  • 9. Numerical 5 (Category 3) 9 Minutes
  • 10. Pipes in series and parallel, Concept of equivalent pipe, Dupuit's equation 14 Minutes
  • 11. Numerical 6 (Pipes in series and parallel) 7 Minutes
  • 11. Numerical 7 (Pipes in series and parallel) 10 Minutes
  • 12. Numerical 8 (Pipes in series and parallel) 10 Minutes
  • 13. Numerical 9 (Pipes in series and parallel, 2075 Baiisakh) 13 Minutes
  • 14. Siphon and its application (intro) 8 Minutes
  • 15. Characteristic parameters of siphon 15 Minutes
  • 16. Numerical 10 (siphon) 8 Minutes
  • 17. Numerical 11 (siphon) 8 Minutes
  • 1. Introduction 12 Minutes
  • 2. Procedure for solving Type 1- Problem (3 reservoir problem) 8 Minutes
  • 3. Numerical (Type 1) 10 Minutes
  • 4. Procedure for solving Type 2-Problem (3 reservoir problem) 8 Minutes
  • 5. Numerical 2 (Type 2) 16 Minutes
  • 6. Procedure for solving Type 3-Problem (3 reservoir problem) 11 Minutes
  • 7. Numerical 3 (Type 3) 27 Minutes
  • 8. Numerical 4 (3 reservoir problem. 2073 Magh) 15 Minutes
  • 9. Numerical 5 (3 reservoir problem, 2073 Bhadra, 2076 Baisakh) 16 Minutes
  • 10. Introduction to pipe network problem 9 Minutes
  • 11. Hardy Cross Method 13 Minutes
  • 12. Numerical 6 (Pipe network problem) 19 Minutes
  • 13. Numerical 7 (Pipe network problem) 32 Minutes
  • 14. Numerical 8 (Pipe network problem, 2071 Bhadra) 14 Minutes
  • 15 Numerical 9 (Pipe network problem, 2072 Magh) 25 Minutes
  • 1. Introduction_1 6 Minutes
  • 2. Equation of motion (unsteady flow) 15 Minutes
  • 3. Analysis of Euler's equation 14 Minutes
  • 4. Numerical 1 (Analysis of Euler's equation) 15 Minutes
  • 5. Numerical 2 (Analysis of Euler's equation) 18 Minutes
  • 6. Numerical 3 (Analysis of Euler's equation) 10 Minutes
  • 7. Numerical 4 (Analysis of Euler's equation) 8 Minutes
  • 8. Continuity equation (unsteady flow) 11 Minutes
  • 9. Water hammer and its effects 13 Minutes
  • 10. Evolution of hydraulic transient waves 13 Minutes
  • 11. Time history of water hammer pressure wave 10 Minutes
  • 12. Pressure rise due to gradual closure of valve 7 Minutes
  • 13. Pressure rise due to sudden closure of valve (rigid pipes) 6 Minutes
  • 14. Pressure rise due to sudden closure of valve (elastic pipes) 11 Minutes
  • 15. Numerical 5 (Pressure rise due to evolution of hydraulic transient waves) 8 Minutes
  • 16. Numerical 6 (Pressure rise due to evolution of transient waves) 9 Minutes
  • 17. Numerical 7 (Pressure rise due to evolution of transient waves) 25 Minutes
  • 18. Numerical 8 (Time history of water hammer pressure wave) 21 Minutes
  • 19. Relief devices against action of water hammer (surge tank) 8 Minutes
  • 1. Introduction 11 Minutes
  • 2. Types of Open Channel 8 Minutes
  • 3. Geometric properties of channel section 8 Minutes
  • 4. Classification of open channel flow 9 Minutes
  • 5. Exam questions 5 Minutes
  • 1. Condition for uniform flow 6 Minutes
  • 2. Expression for shear stress acting on the channel boundary 7 Minutes
  • 3. Uniform flow formula 5 Minutes
  • 4. Factors affecting Manning's n 7 Minutes
  • 5. Velocity Distribution 12 Minutes
  • 6. Some terms in uniform flow computation 13 Minutes
  • 7. Solution of uniform flow problems 6 Minutes
  • 8. Numerical 1 (Uniform flow) 16 Minutes
  • 9. Numerical 2 (Uniform flow) 4 Minutes
  • 10. Numerical 3 (Uniform flow) 8 Minutes
  • 11. Most efficient channel section condition 3 Minutes
  • 12. Most efficient rectangular channel 5 Minutes
  • 13. Numerical 4 (most economic rectangular channel) 9 Minutes
  • 14. Most efficient triangular channel 7 Minutes
  • 15. Numerical 5 (most economic triangular channel) 5 Minutes
  • 16. Most efficient trapezoidal channel 16 Minutes
  • 17. Numerical 6 (most economic trapezoidal channel) 8 Minutes
  • 18. Numerical 6 (most efficient trapezoidal section) 8 Minutes
  • 19. Numerical 7 (Trapezoidal section, 2073 Bhadra) 8 Minutes
  • 20. Most efficient circular channel (condition for maximum velocity) 15 Minutes
  • 21. Most efficient circular channel section (condition for maximum discharge) 12 Minutes
  • 22. Numerical 8 (most economic circular channel section) 8 Minutes
  • 23. Numerical 7 (Circular channel section, 2074 Bhadra) 10 Minutes
  • 1. Specific energy 9 Minutes
  • 2. Specific energy curve, condition for critical flow 13 Minutes
  • 3. Specific energy, critical depth for rectangular channel 7 Minutes
  • 4. Numerical 1 (rectangular channel) 10 Minutes
  • 5. Numerical 2 (rectangular channel) 5 Minutes
  • 6. Numerical 3 (rectangular channel) 8 Minutes
  • 7. Numerical 4 (rectangular channel, 2068 Magh) 4 Minutes
  • 8. Specific energy, critical depth for triangular channel 6 Minutes
  • 9. Numerical 5 (triangular channel) 7 Minutes
  • 10. Specific energy, critical depth for trapezoidal channel 6 Minutes
  • 11. Numerical 6 (Trapezoidal channel) 12 Minutes
  • 12. Numerical 7 (Trapezoidal channel) 9 Minutes
  • 13. Discharge-depth curve for a given specific energy 7 Minutes
  • 14. Maximum discharge for a rectangular channel section 6 Minutes
  • 15. Critical flow and its computation 9 Minutes
  • 16. Section factor and Hydraulic exponent during critical flow computation 6 Minutes
  • 17. Occurence of critical depth 10 Minutes
  • 18. Numerical 8 (Critical flow computation) 29 Minutes
  • 19. Application of energy principle and critical depth concept 14 Minutes
  • 20. Numerical 9 (Provision of hump) 14 Minutes
  • 21. Numerical 10 (Provision of hump) 9 Minutes
  • 22. Numerical 11 (2076 Baisakh) 15 Minutes
  • 23. Numerical 12(Channel with contraction of width) 17 Minutes
  • 24. Numerical 12 (channel transition, both in cross section and bed slope) 12 Minutes
  • 25. Numerical 13 (channel transition, 2074 Bhadra) 9 Minutes
  • 26. Momentum principle in open channel flow 8 Minutes
  • 27. Specific force, Specific force curve and condition for critical flow 12 Minutes
  • 28. Conjugate depths and relation between them, related question 8 Minutes
  • 29. Question based on relation between conjugate depth(2076 Baisakh) 6 Minutes
  • 1. Introduction 8 Minutes
  • 2. Differential equation for the GVF 10 Minutes
  • 3. Modified forms of GVF equations 10 Minutes
  • 4. Classification of flow surface profiles 14 Minutes
  • 5. Characteristics and analysis of flow profiles 9 Minutes
  • 6. Mild slope profile (M1, M2 and M3) 15 Minutes
  • 7. Profiles in steep slope (S1, S2 and S3) 18 Minutes
  • 8. Profiles in critical slope (C1 and C3) 9 Minutes
  • 9. Profiles in horizontal and adverse slopes (H2, H3, A2 and A3) 8 Minutes
  • 10. Analysis of flow profile (break in grades) 17 Minutes
  • 11. Numerical (Analysis of flow in GVF) 16 Minutes
  • 12. Direct step method 11 Minutes
  • 13. Numerical (Direct step method) 26 Minutes
  • 14. Numerical (Direct step method) 18 Minutes
  • 15. Standard step method 12 Minutes
  • 16. Numerical (Standard step method) 16 Minutes
  • 17. Graphical integration method 6 Minutes
  • 18. Direct integration method 13 Minutes
  • 19. Numerical (Direct integration method) 19 Minutes
  • 20. Bresse's method 7 Minutes
  • 21. Numerical (Bresse's method) 15 Minutes
  • 1. Introduction 7 Minutes
  • 2. Hydraulic jump phenomenon 5 Minutes
  • 3. Relationship between sequent depths 14 Minutes
  • 4. Energy loss in hydraulic jump 8 Minutes
  • 5. Length, height and efficiency of jump 3 Minutes
  • 6. Classification of the hydraulic jump 13 Minutes
  • 7. Relation between Fr1 and Fr2 5 Minutes
  • 8. Numerical 1 15 Minutes
  • 9. Numerical 2 11 Minutes
  • 10. Numerical 3 (2073 Bhadra) 7 Minutes
  • 11. Numerical 4 12 Minutes
  • 12. Numerical 5 12 Minutes
  • 1. Introduction to rigid and mobile boundary channel 5 Minutes
  • 2. Design principle of rigid boundary channel (minimum permissible velocity approach) 6 Minutes
  • 3. Example (Minimum permissible velocity approach) 6 Minutes
  • 4. Definition of alluvial channel, shear stress distribution on channel boundary, incipient motion condition 7 Minutes
  • 5. Design of mobile boundary channel (maximum permissible velocity approach) 8 Minutes
  • 6. Numerical example (Maximum permissible velocity method) 6 Minutes
  • 7. Tractive force method (distribution of tractive force) 9 Minutes
  • 8 Tractive force ratio 12 Minutes
  • 9. Shield's tractive force theory 14 Minutes
  • 10. Numerical (Shield's tractive force theory) 6 Minutes
  • 11. Design steps of channel by tractive force method 3 Minutes
  • 12. Numerical (Tractive force method) 13 Minutes
  • 13. Design with regime approach (Kennedy's silt theory and Lindley's regime theory) 8 Minutes
  • 14. Lacey's regime theory (design steps) 6 Minutes
  • 15. Numerical (Lacey's regime approach) 6 Minutes
  • 16. Numerical (2068 Bhadra, similar question in 2076 baisakh) 10 Minutes
  • 17. Numerical (2068 magh, 2071 magh) 6 Minutes
  • 18. Formation of river beds based on shear stress 10 Minutes
  • 1. Chapter 7 (determination of upstream and downstream depth when there is hump in the downstream) 28 Minutes
  • 2. Chapter 8 (calculation of normal depth and critical depth in wide rectangular channel) 11 Minutes
  • 3. Chapter 8 (determination of normal depth in trapezoidal channel) 23 Minutes
  • 4. Chapter 9 (calculation of sequent depths and energy loss during hydraulic jump) 11 Minutes
  • 2075 Bhadra
    • 1. Q. No. 1.a 7 Minutes
    • 2. Q. No. 1.b 9 Minutes
    • 3. Q. No. 2.a 6 Minutes
    • 4. Q. No.2.b 28 Minutes
    • 5. Q. No. 3.a 15 Minutes
    • 6. Q. No. 3.b 7 Minutes
    • 7. Q. No. 4.a 12 Minutes
    • 8. Q. No.4.b 4 Minutes
    • 9.1 Q. No. 4.c 10 Minutes
    • 10. Q. No. 5.a 6 Minutes
    • 11. Q. No. 5.b 8 Minutes
    2076 Baisakh
    • 1. Q. No. 1.a 17 Minutes
    • 2. Q. No. 1.b 13 Minutes
    • 3. Q. No. 2.a 14 Minutes
    • 4. Q. No. 2.b 10 Minutes
    • 5. Q. No. 3.a 8 Minutes
    • 6. Q. No. 3.b 5 Minutes
    • 7. Q. No. 3.c 17 Minutes
    • 8. Q. No. 4.a 9 Minutes
    • 9. Q. No. 4.b 13 Minutes
    • 10. Q. No. 5.a 10 Minutes
    • 11. Q. No. 5.b 14 Minutes
    2076 Bhadra
    • 1. Q. No. 1.a 15 Minutes
    • 2. Q. No. 1.b 9 Minutes
    • 3. Q. No. 1.c 9 Minutes
    • 4. Q. No. 2.a 28 Minutes
    • 5. Q. No. 2.b 10 Minutes
    • 6. Q. No. 3.a 5 Minutes
    • 7. Q. No. 3.b 5 Minutes
    • 8. Q. No. 3.c 8 Minutes
    • 9. Q. No. 4.a 5 Minutes
    • 10. Q. No. 4.b 9 Minutes
    • 11. Q. No. 4.c 3 Minutes
    • 12. Q, No. 5.a 14 Minutes
    • 13. Q. No. 5.b 9 Minutes
    2077 Poush
    • 1. Q. No. 1.a 24 Minutes
    • 2. Q. No. 1.b 11 Minutes
    • 3. Q. No. 2.a 14 Minutes
    • 4. Q. No. 2.b 7 Minutes
    • 5. Q. No. 3.a 12 Minutes
    • 6. Q. No. 3.b 3 Minutes
    • 7. Q. No. 3.c 11 Minutes
    • 8. Q. No. 4.a 13 Minutes
    • 9. Q. No. 4.b 12 Minutes
    • 10. Q. No. 5.a 13 Minutes
    • 11. Q. No. 5.b 10 Minutes
    2078 Baisakh
    • 1. Q. No. 1.a 14 Minutes
    • 2. Q. No. 1.b 6 Minutes
    • 3. Q. No. 2.a 13 Minutes
    • 4. Q. No. 2.b 13 Minutes
    • 5. Q. No. 3.a 2 Minutes
    • 6. Q. No. 3.b 14 Minutes
    • 7. Q. No. 3.c 7 Minutes
    • 8. Q. No. 4.a 10 Minutes
    • 9. Q. No. 4.b 22 Minutes
    • 10. Q. No. 5.a 24 Minutes
    • 11. Q. No. 5.b 16 Minutes
    Requirements
    • Students are required to have knowledge of Hydraulics, based on syllabus of IoE
    Description

    The videos herein are strictly based on syllabus of Institute of Engineering Tribhuvan University, Nepal promoting "e-Learning in Nepal" and are made with intention to provide guidance to the "Bachelor in Engineering(BE) appearing students", for securing good results. The course tries to cover all the basics of Hydraulics. This course also comprises also have the solution of  most frequently asked questions in final exam of BE with numerical. We strongly believe that, viewers will be benefited from these videos and the thirst of curiosity of viewers will be quenched! Feedbacks and suggestion to improve are always welcome and highly appreciated!

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    • 258 Lessons
    • 30 Days Subscription
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