Hydraulics

Hydraulics Bachelor of Engineering(BE) videos According to syllabus of Institute of Engineering(IOE), Tribhuvan University (TU)

Advanced 5 (3 Reviews ) 13 Students enrolled
Created by Mero School Last updated Thu, 25-Nov-2021 Nepali
What will I learn?
  • After Completion of this Course, Students will get complete knowledge of hydraulics, based on syllabus of IoE and will be able to secure good score in IoE exam.

Curriculum for this course
241 Lessons 45:00:21 H:M:S
1. Marks Distribution
1 Lessons 00:05:23 Hours
  • Syllabus and Marks distribution 00:05:23 Free
  • 1. Pipe flow (differences between pipe flow and open channel flow) 00:13:16 Free
  • 2. Reynold's experiment and flow based on Reynold's number 00:08:48 Free
  • 3. Laminar flow in circular pipe (expression for shear stress) 00:14:48
  • 4. Laminar flow in circular pipe (velocity distribution) 00:08:56
  • 5. Relation between average velocity and maximum velocity 00:09:11
  • 6. Laminar flow in circular pipe (head loss) 00:07:35
  • 7. Numerical 1 (laminar flow) 00:24:04
  • 8. Numerical 2 (laminar flow) 00:19:41
  • 9. K.E. and momentum correction factors 00:07:27
  • 10. Calculation of K.E. and momentum correction factors for laminar flow 00:10:36
  • 11. Turbulent flow (basic features) 00:09:32
  • 12. Shear stress development in turbulent flow 00:05:44
  • 13. Boussinesq theory of turbulence 00:04:38
  • 14. Reynold's principle of turbulence 00:05:37
  • 15. Prandtl's mixing length theory 00:08:37
  • 16. Velocity distribution for turbulent flow (Prandtl's universal velocity distribution, applicable for both smooth and rough pipe) 00:12:53
  • 17. Analysis of velocity distribution in turbulent flow 00:08:27
  • 18. Hydrodynamically smooth and rough pipe 00:07:18
  • 19. Velocity distribution equation for turbulent flow in smooth pipe 00:13:09
  • 20. Velocity distribution equation for turbulent flow inrough pipe 00:04:47
  • 21. Velocity distribution equation in terms of mean velocity 00:09:13
  • 22. Relation between velocity at any point and average velocity, location of average velocity 00:08:51
  • 23. Darcy-Weisbach equation 00:17:15
  • 24. Resistance to flow of fluid in smooth and rough pipes 00:24:15
  • 25. Numerical 1 (Turbulent flow) 00:16:05
  • 26. Numerical 2 (Turbulent flow) 00:10:06
  • 27. Numerical 3 (Turbulent flow) 00:10:33
  • 28. Numerical 4 (Turbulent flow, concept of hydraulic radius) 00:15:30
  • 29. Numerical 5 (Turbulent flow) 00:13:55
  • 30. Energy losses in pipe 00:05:56
  • 31. Loss of head due to sudden enlargement of pipe 00:08:24
  • 32. Head loss due to sudden contraction of pipe 00:07:37
  • 33. Other types of minor losses 00:05:29
  • 34. HGL and TEL 00:09:58
  • 35. Numerical (minor losses) 00:11:55
  • 36. Numerical (HGL and TEL) 00:25:15
  • 1. Three categories of pipe flow problems 00:07:07
  • 2. Category 1 (procedure to solve) 00:03:32
  • 3. Numerical (Category 1) 00:06:40
  • 4. Category 2 (procedure for solving) 00:05:09
  • 5. Numerical 2 (Category 2) 00:11:07
  • 6. Numerical 4 (Category 2) 00:08:01
  • 7. Category 3 (procedure for solving) 00:04:27
  • 8. Numerical 4 (Category 3) 00:10:27
  • 9. Numerical 5 (Category 3) 00:09:28
  • 10. Pipes in series and parallel, Concept of equivalent pipe, Dupuit's equation 00:14:52
  • 11. Numerical 6 (Pipes in series and parallel) 00:07:58
  • 12. Numerical 7 (Pipes in series and parallel) 00:10:37
  • 13. Numerical 8 (Pipes in series and parallel) 00:10:16
  • 14. Numerical 9 (Pipes in series and parallel, 2075 Baiisakh) 00:13:10
  • 15. Siphon and its application (intro) 00:08:01
  • 16. Characteristic parameters of siphon 00:15:54
  • 17. Numerical 10 (siphon) 00:08:03
  • 18. Numerical 11 (siphon) 00:08:01
  • 1. Introduction 00:12:23
  • 2. Procedure for solving Type 1- Problem (3 reservoir problem) 00:08:10
  • 3. Numerical (Type 1) 00:10:59
  • 4. Procedure for solving Type 2-Problem (3 reservoir problem) 00:08:51
  • 5. Numerical 2 (Type 2) 00:16:40
  • 6. Procedure for solving Type 3-Problem (3 reservoir problem) 00:11:29
  • 7. Numerical 3 (Type 3) 00:27:29
  • 8. Numerical 4 (3 reservoir problem. 2073 Magh) 00:15:50
  • 9. Numerical 5 (3 reservoir problem, 2073 Bhadra, 2076 Baisakh) 00:16:59
  • 10. Introduction to pipe network problem 00:09:47
  • 11. Hardy Cross Method 00:13:12
  • 12. Numerical 6 (Pipe network problem) 00:19:57
  • 13. Numerical 7 (Pipe network problem) 00:32:42
  • 14. Numerical 8 (Pipe network problem, 2071 Bhadra) 00:14:30
  • 15 Numerical 9 (Pipe network problem, 2072 Magh) 00:25:04
  • 1. Introduction_1 00:06:18
  • 2. Equation of motion (unsteady flow) 00:15:39
  • 3. Analysis of Euler's equation 00:14:54
  • 4. Numerical 1 (Analysis of Euler's equation) 00:15:53
  • 5. Numerical 2 (Analysis of Euler's equation) 00:18:17
  • 6. Numerical 3 (Analysis of Euler's equation) 00:10:10
  • 7. Numerical 4 (Analysis of Euler's equation) 00:08:18
  • 8. Continuity equation (unsteady flow) 00:11:22
  • 9. Water hammer and its effects 00:13:17
  • 10. Evolution of hydraulic transient waves 00:13:26
  • 11. Time history of water hammer pressure wave 00:10:08
  • 12. Pressure rise due to gradual closure of valve 00:07:10
  • 13. Pressure rise due to sudden closure of valve (rigid pipes) 00:06:04
  • 14. Pressure rise due to sudden closure of valve (elastic pipes) 00:11:35
  • 15. Numerical 5 (Pressure rise due to evolution of hydraulic transient waves) 00:08:04
  • 16. Numerical 6 (Pressure rise due to evolution of transient waves) 00:09:14
  • 17. Numerical 7 (Pressure rise due to evolution of transient waves) 00:25:32
  • 18. Numerical 8 (Time history of water hammer pressure wave) 00:21:37
  • 19. Relief devices against action of water hammer (surge tank) 00:08:39
  • 1. Introduction 00:11:13
  • 2. Types of Open Channel 00:08:22
  • 3. Geometric properties of channel section 00:08:08
  • 4. Classification of open channel flow 00:09:41
  • 5. Exam questions 00:05:25
  • 1. Condition for uniform flow 00:06:50
  • 2. Expression for shear stress acting on the channel boundary 00:07:14
  • 3. Uniform flow formula 00:05:26
  • 4. Factors affecting Manning's n 00:07:34
  • 5. Velocity Distribution 00:12:00
  • 6. Some terms in uniform flow computation 00:13:04
  • 7. Solution of uniform flow problems 00:06:53
  • 8. Numerical 1 (Uniform flow) 00:16:14
  • 9. Numerical 2 (Uniform flow) 00:04:41
  • 10. Numerical 3 (Uniform flow) 00:08:36
  • 11. Most efficient channel section condition 00:03:57
  • 12. Most efficient rectangular channel 00:05:11
  • 13. Numerical 4 (most economic rectangular channel) 00:09:39
  • 14. Most efficient triangular channel 00:07:05
  • 15. Numerical 5 (most economic triangular channel) 00:05:55
  • 16. Most efficient trapezoidal channel 00:16:06
  • 17. Numerical 6 (most economic trapezoidal channel) 00:08:44
  • 18. Numerical 6 (most efficient trapezoidal section) 00:08:43
  • 19. Numerical 7 (Trapezoidal section, 2073 Bhadra) 00:08:38
  • 20. Most efficient circular channel (condition for maximum velocity) 00:15:10
  • 21. Most efficient circular channel section (condition for maximum discharge) 00:12:30
  • 22. Numerical 8 (most economic circular channel section) 00:08:43
  • 23. Numerical 7 (Circular channel section, 2074 Bhadra) 00:10:18
  • 1. Specific energy 00:09:15
  • 2. Specific energy curve, condition for critical flow 00:13:46
  • 3. Specific energy, critical depth for rectangular channel 00:07:04
  • 4. Numerical 1 (rectangular channel) 00:10:36
  • 5. Numerical 2 (rectangular channel) 00:05:11
  • 6. Numerical 3 (rectangular channel) 00:08:53
  • 7. Numerical 4 (rectangular channel, 2068 Magh) 00:04:39
  • 8. Specific energy, critical depth for triangular channel 00:06:20
  • 9. Numerical 5 (triangular channel) 00:07:25
  • 10. Specific energy, critical depth for trapezoidal channel 00:06:54
  • 11. Numerical 6 (Trapezoidal channel) 00:12:02
  • 12. Numerical 7 (Trapezoidal channel) 00:09:10
  • 13. Discharge-depth curve for a given specific energy 00:07:35
  • 14. Maximum discharge for a rectangular channel section 00:06:33
  • 15. Critical flow and its computation 00:09:14
  • 16. Section factor and Hydraulic exponent during critical flow computation 00:06:50
  • 17. Occurence of critical depth 00:10:15
  • 18. Numerical 8 (Critical flow computation) 00:29:16
  • 19. Application of energy principle and critical depth concept 00:14:40
  • 20. Numerical 9 (Provision of hump) 00:14:27
  • 21. Numerical 10 (Provision of hump) 00:09:43
  • 22. Numerical 11 (2076 Baisakh) 00:15:00
  • 23. Numerical 12(Channel with contraction of width) 00:17:22
  • 24. Numerical 12 (channel transition, both in cross section and bed slope) 00:12:37
  • 25. Numerical 13 (channel transition, 2074 Bhadra) 00:09:04
  • 26. Momentum principle in open channel flow 00:08:27
  • 27. Specific force, Specific force curve and condition for critical flow 00:12:35
  • 28. Conjugate depths and relation between them, related question 00:08:34
  • 29. Question based on relation between conjugate depth(2076 Baisakh) 00:06:25
  • 1. Introduction 00:08:35
  • 2. Differential equation for the GVF 00:10:47
  • 3. Modified forms of GVF equations 00:10:57
  • 4. Classification of flow surface profiles 00:14:02
  • 5. Characteristics and analysis of flow profiles 00:09:58
  • 6. Mild slope profile (M1, M2 and M3) 00:15:35
  • 7. Profiles in steep slope (S1, S2 and S3) 00:18:32
  • 8. Profiles in critical slope (C1 and C3) 00:09:21
  • 9. Profiles in horizontal and adverse slopes (H2, H3, A2 and A3) 00:08:07
  • 10. Analysis of flow profile (break in grades) 00:17:27
  • 11. Numerical (Analysis of flow in GVF) 00:16:40
  • 12. Direct step method 00:11:49
  • 13. Numerical (Direct step method) 00:26:23
  • 14. Numerical (Direct step method) 00:18:02
  • 15. Standard step method 00:12:01
  • 16. Numerical (Standard step method) 00:16:34
  • 17. Graphical integration method 00:06:22
  • 18. Direct integration method 00:13:30
  • 19. Numerical (Direct integration method) 00:19:40
  • 20. Bresse's method 00:07:58
  • 21. Numerical (Bresse's method) 00:15:27
  • 1. Introduction 00:07:37
  • 2. Hydraulic jump phenomenon 00:05:33
  • 3. Relationship between sequent depths 00:14:06
  • 4. Energy loss in hydraulic jump 00:08:38
  • 5. Length, height and efficiency of jump 00:03:43
  • 6. XClassification of the hydraulic jump 00:08:38
  • 7. Relation between Fr1 and Fr2 00:05:50
  • 8. Numerical 1 00:15:54
  • 9. Numerical 2 00:11:26
  • 10. Numerical 3 (2073 Bhadra) 00:07:51
  • 11. Numerical 4 00:12:35
  • 12. Numerical 5 00:12:33
  • 1. Introduction to rigid and mobile boundary channel 00:05:42
  • 2. Design principle of rigid boundary channel (minimum permissible velocity approach) 00:06:30
  • 3. Example (Minimum permissible velocity approach) 00:06:49
  • 4. Definition of alluvial channel, shear stress distribution on channel boundary, incipient motion condition 00:07:45
  • 5. Design of mobile boundary channel (maximum permissible velocity approach) 00:08:28
  • 6. Numerical example (Maximum permissible velocity method) 00:06:55
  • 7. Tractive force method (distribution of tractive force) 00:09:57
  • 8 Tractive force ratio 00:12:56
  • 9. Shield's tractive force theory 00:14:16
  • 10. Numerical (Shield's tractive force theory) 00:06:05
  • 11. Design steps of channel by tractive force method 00:03:38
  • 12. Numerical (Tractive force method) 00:13:00
  • 13. Design with regime approach (Kennedy's silt theory and Lindley's regime theory) 00:08:14
  • 14. Lacey's regime theory (design steps) 00:06:32
  • 15. Numerical (Lacey's regime approach) 00:06:46
  • 16. Numerical (2068 Bhadra, similar question in 2076 baisakh) 00:10:55
  • 17. Numerical (2068 magh, 2071 magh) 00:06:23
  • 18. Formation of river beds based on shear stress 00:10:41
  • 1. Chapter 7 (determination of upstream and downstream depth when there is hump in the downstream) 00:28:44
  • 2. Chapter 8 (calculation of normal depth and critical depth in wide rectangular channel) 00:11:46
  • 3. Chapter 8 (determination of normal depth in trapezoidal channel) 00:23:11
  • 4. Chapter 9 (calculation of sequent depths and energy loss during hydraulic jump) 00:11:49
  • 2075 Bhadra
    • 1. Q. No. 1.a 00:07:14
    • 2. Q. No. 1.b 00:09:53
    • 3. Q. No. 2.a 00:06:44
    • 4. Q. No.2.b 00:28:52
    • 5. Q. No. 3.a 00:15:47
    • 6. Q. No. 3.b 00:07:55
    • 7. Q. No. 4.a 00:12:44
    • 8. Q. No.4.b 00:04:12
    • 9.1 Q. No. 4.c 00:10:13
    • 10. Q. No. 5.a 00:06:47
    • 11. Q. No. 5.b 00:08:48
    2076 Baisakh
    • 1. Q. No. 1.a 00:17:10
    • 2. Q. No. 1.b 00:13:49
    • 3. Q. No. 2.a 00:14:03
    • 4. Q. No. 2.b 00:10:32
    • 5. Q. No. 3.a 00:08:15
    • 6. Q. No. 3.b 00:05:12
    • 7. Q. No. 3.c 00:17:59
    • 8. Q. No. 4.a 00:09:51
    • 9. Q. No. 4.b 00:13:42
    • 10. Q. No. 5.a 00:10:56
    • 11. Q. No. 5.b 00:14:26
    2077 Poush
    • 1. Q. No. 1.a 00:24:11
    • 2. Q. No. 1.b 00:11:28
    • 3. Q. No. 2.a 00:14:51
    • 4. Q. No. 2.b 00:07:57
    • 5. Q. No. 3.a 00:12:03
    • 6. Q. No. 3.b 00:03:50
    • 7. Q. No. 3.c 00:11:07
    • 8. Q. No. 4.b 00:13:48
    • 9. Q. No. 4.b 00:12:54
    • 10. Q. No. 5.a 00:13:50
    • 11. Q. No. 5.b 00:10:17
    2078 Baisakh
    • 1. Q. No. 1.a_1 00:14:55
    • 2. Q. No. 1.b_1 00:06:03
    • 3. Q. No. 2.a_1 00:13:09
    • 4. Q. No. 2.b_1 00:13:05
    • 5. Q. No. 3.a_1 00:02:53
    • 6. Q. No. 3.b_1 00:14:51
    • 7. Q. No. 3.c_1 00:07:54
    Requirements
    • Students are required to have knowledge of Hydraulics, based on syllabus of IoE
    + View more
    Description

    The videos herein are strictly based on syllabus of Institute of Engineering Tribhuvan University, Nepal promoting "e-Learning in Nepal" and are made with intention to provide guidance to the "Bachelor in Engineering(BE) appearing students", for securing good results. The course tries to cover all the basics of Hydraulics. This course also comprises also have the solution of  most frequently asked questions in final exam of BE with numerical. We strongly believe that, viewers will be benefited from these videos and the thirst of curiosity of viewers will be quenched! Feedbacks and suggestion to improve are always welcome and highly appreciated!

    Student Feedback
    5
    Average rating
    • 0%
    • 0%
    • 33%
    • 0%
    • 67%
    Reviews
    Rs 999
    Buy now
    Includes:
    • 45:00:21 On demand videos
    • 241 Lessons
    • 30 Days Subscription
    • Access On Mobile And Web